texplorer1994
Active Member
- Joined
- March 18, 2002
- Messages
- 55
- Reaction score
- 0
- City, State
- Houston, Texas
- Year, Model & Trim Level
- 1994 XL
Okay, I need a little clarification on this. I was taught that to calculate the ohm load there are two equations. One for series and one for parallel. For a series it is the total ohm load and for parallel it is the inverse of 1 over each ohm load added.
Series
4 ohms + 4 ohms = 8 ohms
Parallel
1/{(1/4)+(1/4)}= 2 ohms
Various people have confused me. A friend of the family has a high end stereo and he was told that the amplifier had to have the ohm load set to take advantage of a different resistance. Another guy at a circuit city told me that an amplifier was set to a 4 ohm load while pushing 3 10 inch 4 ohm subs. Maybe my math sucks, but I don't see any possible way a resistance of 4 ohms could be achieved. Am I confused or do the speakers actually provide the resistance? Is there any way to set the ohm load on the amp? I am incredibly bothered by this.
Series
4 ohms + 4 ohms = 8 ohms
Parallel
1/{(1/4)+(1/4)}= 2 ohms
Various people have confused me. A friend of the family has a high end stereo and he was told that the amplifier had to have the ohm load set to take advantage of a different resistance. Another guy at a circuit city told me that an amplifier was set to a 4 ohm load while pushing 3 10 inch 4 ohm subs. Maybe my math sucks, but I don't see any possible way a resistance of 4 ohms could be achieved. Am I confused or do the speakers actually provide the resistance? Is there any way to set the ohm load on the amp? I am incredibly bothered by this.